Databases and SQL
Filtering
Learning Objectives
- Write queries that select records that satisfy user-specified conditions.
- Explain the order in which the clauses in a query are executed.
One of the most powerful features of a database is the ability to filter data, i.e., to select only those records that match certain criteria. For example, suppose we want to see when a particular site was visited. We can select these records from the Visited
table by using a WHERE
clause in our query:
SELECT * FROM Visited WHERE site='DR-1';
id | site | dated |
---|---|---|
619 | DR-1 | 1927-02-08 |
622 | DR-1 | 1927-02-10 |
844 | DR-1 | 1932-03-22 |
The database manager executes this query in two stages. First, it checks at each row in the Visited
table to see which ones satisfy the WHERE
. It then uses the column names following the SELECT
keyword to determine which columns to display.
This processing order means that we can filter records using WHERE
based on values in columns that aren’t then displayed:
SELECT id FROM Visited WHERE site='DR-1';
id |
---|
619 |
622 |
844 |
We can use many other Boolean operators to filter our data. For example, we can ask for all information from the DR-1 site collected before 1930:
SELECT * FROM Visited WHERE site='DR-1' AND dated<'1930-01-01';
id | site | dated |
---|---|---|
619 | DR-1 | 1927-02-08 |
622 | DR-1 | 1927-02-10 |
If we want to find out what measurements were taken by either Lake or Roerich, we can combine the tests on their names using OR
:
SELECT * FROM Survey WHERE person='lake' OR person='roe';
taken | person | quant | reading |
---|---|---|---|
734 | lake | sal | 0.05 |
751 | lake | sal | 0.1 |
752 | lake | rad | 2.19 |
752 | lake | sal | 0.09 |
752 | lake | temp | -16.0 |
752 | roe | sal | 41.6 |
837 | lake | rad | 1.46 |
837 | lake | sal | 0.21 |
837 | roe | sal | 22.5 |
844 | roe | rad | 11.25 |
Alternatively, we can use IN
to see if a value is in a specific set:
SELECT * FROM Survey WHERE person IN ('lake', 'roe');
taken | person | quant | reading |
---|---|---|---|
734 | lake | sal | 0.05 |
751 | lake | sal | 0.1 |
752 | lake | rad | 2.19 |
752 | lake | sal | 0.09 |
752 | lake | temp | -16.0 |
752 | roe | sal | 41.6 |
837 | lake | rad | 1.46 |
837 | lake | sal | 0.21 |
837 | roe | sal | 22.5 |
844 | roe | rad | 11.25 |
We can combine AND
with OR
, but we need to be careful about which operator is executed first. If we don’t use parentheses, we get this:
SELECT * FROM Survey WHERE quant='sal' AND person='lake' OR person='roe';
taken | person | quant | reading |
---|---|---|---|
734 | lake | sal | 0.05 |
751 | lake | sal | 0.1 |
752 | lake | sal | 0.09 |
752 | roe | sal | 41.6 |
837 | lake | sal | 0.21 |
837 | roe | sal | 22.5 |
844 | roe | rad | 11.25 |
which is salinity measurements by Lake, and any measurement by Roerich. We probably want this instead:
SELECT * FROM Survey WHERE quant='sal' AND (person='lake' OR person='roe');
taken | person | quant | reading |
---|---|---|---|
734 | lake | sal | 0.05 |
751 | lake | sal | 0.1 |
752 | lake | sal | 0.09 |
752 | roe | sal | 41.6 |
837 | lake | sal | 0.21 |
837 | roe | sal | 22.5 |
We can also filter by partial matches. For example, if we want to know something just about the site names beginning with “DR” we can use the LIKE
keyword. The percent symbol acts as a wildcard, matching any characters in that place. It can be used at the beginning, middle, or end of the string:
SELECT * FROM Visited WHERE site LIKE 'DR%';
id | site | dated |
---|---|---|
619 | DR-1 | 1927-02-08 |
622 | DR-1 | 1927-02-10 |
734 | DR-3 | 1930-01-07 |
735 | DR-3 | 1930-01-12 |
751 | DR-3 | 1930-02-26 |
752 | DR-3 | |
844 | DR-1 | 1932-03-22 |
Finally, we can use DISTINCT
with WHERE
to give a second level of filtering:
SELECT DISTINCT person, quant FROM Survey WHERE person='lake' OR person='roe';
person | quant |
---|---|
lake | sal |
lake | rad |
lake | temp |
roe | sal |
roe | rad |
But remember: DISTINCT
is applied to the values displayed in the chosen columns, not to the entire rows as they are being processed.
What we have just done is how most people “grow” their SQL queries. We started with something simple that did part of what we wanted, then added more clauses one by one, testing their effects as we went. This is a good strategy — in fact, for complex queries it’s often the only strategy — but it depends on quick turnaround, and on us recognizing the right answer when we get it.
The best way to achieve quick turnaround is often to put a subset of data in a temporary database and run our queries against that, or to fill a small database with synthesized records. For example, instead of trying our queries against an actual database of 20 million Australians, we could run it against a sample of ten thousand, or write a small program to generate ten thousand random (but plausible) records and use that.
Fix This Query
Suppose we want to select all sites that lie more than 30 degrees from the poles. Our first query is:
SELECT * FROM Site WHERE (lat > -60) OR (lat < 60);
Explain why this is wrong, and rewrite the query so that it is correct.
Finding Outliers
Normalized salinity readings are supposed to be between 0.0 and 1.0. Write a query that selects all records from Survey
with salinity values outside this range.
Matching Patterns
Which of these expressions are true?
'a' LIKE 'a'
'a' LIKE '%a'
'beta' LIKE '%a'
'alpha' LIKE 'a%%'
'alpha' LIKE 'a%p%'